8 lines
No EOL
341 B
Text
8 lines
No EOL
341 B
Text
// we can compare numbers up to 2^(pbits - 2) - 1, ie any number which fits in (pbits - 2) bits
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// lt should work for the maxvalue = 2^(pbits - 2) - 1
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def main(a):
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pbits = 254
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// maxvalue = 2**252 - 1
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maxvalue = 7237005577332262213973186563042994240829374041602535252466099000494570602496 - 1
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return if 0 < maxvalue then 1 else 0 fi |