15 lines
2 KiB
Text
15 lines
2 KiB
Text
// SHA-256 is specified in FIPS 180-3 and initial values are listed in section 5.3.3
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// https://csrc.nist.gov/csrc/media/publications/fips/180/3/archive/2008-10-31/documents/fips180-3_final.pdf
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def main() -> (bool[256]):
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bool[32] h0 = [false, true, true, false, true, false, true, false, false, false, false, false, true, false, false, true, true, true, true, false, false, true, true, false, false, true, true, false, false, true, true, true]
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bool[32] h1 = [true, false, true, true, true, false, true, true, false, true, true, false, false, true, true, true, true, false, true, false, true, true, true, false, true, false, false, false, false, true, false, true]
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bool[32] h2 = [false, false, true, true, true, true, false, false, false, true, true, false, true, true, true, false, true, true, true, true, false, false, true, true, false, true, true, true, false, false, true, false]
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bool[32] h3 = [true, false, true, false, false, true, false, true, false, true, false, false, true, true, true, true, true, true, true, true, false, true, false, true, false, false, true, true, true, false, true, false]
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bool[32] h4 = [false, true, false, true, false, false, false, true, false, false, false, false, true, true, true, false, false, true, false, true, false, false, true, false, false, true, true, true, true, true, true, true]
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bool[32] h5 = [true, false, false, true, true, false, true, true, false, false, false, false, false, true, false, true, false, true, true, false, true, false, false, false, true, false, false, false, true, true, false, false]
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bool[32] h6 = [false, false, false, true, true, true, true, true, true, false, false, false, false, false, true, true, true, true, false, true, true, false, false, true, true, false, true, false, true, false, true, true]
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bool[32] h7 = [false, true, false, true, true, false, true, true, true, true, true, false, false, false, false, false, true, true, false, false, true, true, false, true, false, false, false, true, true, false, false, true]
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bool[256] IV = [...h0, ...h1, ...h2, ...h3, ...h4, ...h5, ...h6, ...h7]
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return IV
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